Question:
The number of common terms in the two sequences: 15, 19, 23, 27, . . . . , 415 and 14, 19, 24, 29, . . . , 464 is
- 18
- 19
- 21
- 20
Correct Answer: Option: 4
Both the sequences are in arithmetic progression.
The common difference (${{d}_{1}}$ ) for the first sequence = 4
The common difference (${{d}_{2}}$ ) for the first sequence = 5
The first term common is 19.
The common terms will also be in arithmetic progression with common difference $LCM\left( {{d}_{1}},{{d}_{2}} \right)=LCM\left( 4,5 \right)=20$
Let there be ‘n’ terms in this sequence, then the last term would be ≤ 415
i.e. $a+\left( n-1 \right)d\le 415$
$\Rightarrow 19+\left( n-1 \right)\times 20\le 415$
$\Rightarrow \left( n-1 \right)\times 20\le 415-19$
$\Rightarrow \left( n-1 \right)\times 20\le 396$
$\Rightarrow \left( n-1 \right)=\left[ \frac{396}{20} \right]$ where [ ] is the greatest integer
$\Rightarrow \left( n-1 \right)=19$
$\Rightarrow n=20$
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