Question:
In a race of three horses, the first beat the second by 11 metres and the third by 90 metres. If the second beat the third by 80 metres, what was the length, in metres, of the racecourse?

Show Answer

Correct Answer: 880

Let the first, second, and third horses be A, B and C respectively. Also, let the length of the racecourse be x.

Therefore,

$\frac{\left( x-11 \right)}{\left( x \right)}=\frac{\left( x-90 \right)}{\left( x-80 \right)}$

$\Rightarrow {{x}^{2}}-91x+880={{x}^{2}}+90x$

$\Rightarrow x=880$


CAT Online Course
Also Check: 841+ CAT Quant Questions with Solutions

CAT 2019 Slot-1


CAT 2019 Slot-2