Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T is
- 5: 6
- 4: 5
- 3: 4
- 2: 3
Correct Answer: Option: 4
Refer to the below figure:
As we can see, the triangle can be divided into 9 concurrent smaller equilateral triangles.
Also, hexagon contains 6 of them.
Hence the required ration = 6/9 =2/3
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