Question:
In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by 6. The revised scores of Anjali, Mohan, and Rama were in the ratio 11:10:3. Then Anjali's score exceeded Rama's score by
- 24
- 26
- 32
- 35
Correct Answer: Option: 3
Let their scores after review be 11x, 10x, and 3x respectively.
Therefore, their scores before review was: (11x-6), 10x-6) and (3x-6) respectively.
Given, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali.
$\Rightarrow \left( 3x-6 \right)=\frac{1}{12}\left[ \left( 11x-6 \right)+\left( 10x-6 \right) \right]$
$\Rightarrow 12\left( 3x-6 \right)=21x-12$
$\Rightarrow 36x-72=21x-12$
$\Rightarrow 36x-21x=72-12=60$
$\Rightarrow x=4$
Now, Anjali’s score – Rama’s score = (11x-6)-(3x-6)=8x =32.
CAT Online Course
Also Check: 841+ CAT Quant Questions with Solutions