Question
If y is a negative number such that \({2^{{y^2}{{\log }_3}5}} = {5^{{{\log }_2}3}}\), then y equals
- \({\log _2}(1/3)\)
- \( - {\log _2}(1/3)\)
- \({\log _2}(1/5)\)
- \( - {\log _2}(1/5)\)
Option: 1
Solution:
Solution:
\({2^{{y^2}{{\log }_3}5}} = {5^{{{\log }_2}3}}\)
\({\left( {{2^{{{\log }_3}5}}} \right)^{{y^2}}} = {5^{{{\log }_2}3}}\)
\({\left( {{5^{{{\log }_3}2}}} \right)^{{y^2}}} = {5^{{{\log }_2}3}}\)
\({5^{{y^2}{{\log }_3}2}} = {5^{{{\log }_2}3}}\)
\( \Rightarrow {y^2}{\log _3}2 = {\log _2}3\)
\({y^2} = \left( {{{\log }_2}3} \right)\left( {{{\log }_2}3} \right)\)
is negative )
\(y = {\log _2}{3^{ - 1}} = {\log _2}\frac{1}{3}\)
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