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# CAT 2020 Quant Question [Slot 3] with Solution 06

Question

Vimla starts for office every day at 9 am and reaches exactly on time if she drives at her usual speed of 40 km/hr. She is late by 6 minutes if she drives at 35 km/hr. One day, she covers two-thirds of her distance to office in one-thirds of her usual time to reach office, and then stops for 8 minutes. The speed, in km/hr, at which she should drive the remaining distance to reach office exactly on time is

1. 29
2. 27
3. 28
4. 26
Option: 3
Solution:

Let the original time taken by Vimla be t minutes $40t/60 = 35 \times (t + 6)/60$

$\Rightarrow t = 35 \times \frac{6}{5} = 42min$

The distance to office =28 km

Required answer $= \frac{{28 \times \frac{1}{3}}}{{42 \times \frac{2}{3} - 8}} \times 60 = 28kmph$

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