Question
Vimla starts for office every day at 9 am and reaches exactly on time if she drives at her usual speed of 40 km/hr. She is late by 6 minutes if she drives at 35 km/hr. One day, she covers two-thirds of her distance to office in one-thirds of her usual time to reach office, and then stops for 8 minutes. The speed, in km/hr, at which she should drive the remaining distance to reach office exactly on time is
- 29
- 27
- 28
- 26
Option: 3
Solution:
Solution:
Let the original time taken by Vimla be t minutes \(40t/60 = 35 \times (t + 6)/60\)
\( \Rightarrow t = 35 \times \frac{6}{5} = 42min\)
The distance to office =28 km
Required answer \( = \frac{{28 \times \frac{1}{3}}}{{42 \times \frac{2}{3} - 8}} \times 60 = 28kmph\)
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