Question
Let C be a circle of radius 5 meters having center at O. Let PQ be a chord of C that passes through points A and B where A is located 4 meters north of O and B is located 3 meters east of O. Then, the length of PQ, in meters, is nearest to
- 7.2
- 7.8
- 6.6
- 8.8
Option: 4
Solution:
Solution:
\(AB = \sqrt {{3^2} + {4^2}} = 5\)
\(OT = \frac{{3 \times 4}}{5} = \frac{{12}}{5}\)
\(OT = 2.4M\)
In \(\Delta OTQ\)
\(O{Q^2} = O{T^2} + T{Q^2} \Rightarrow T{Q^2} = O{Q^2} - O{T^2}\)
\( = {(5)^2} - {(2.4)^2}\)
=19.24
\( \Rightarrow TQ = \sqrt {19.24} \approx 4.4\)
\(\therefore PQ = 2TQ = 8.8m\)
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