Bodhee Prep-Online CAT Coaching | Online CAT Preparation | CAT Online Courses

Get 10% OFF on CAT 24 Course. Code: BODHEE10. Valid till 15th May Enroll Now

CAT 2020 Quant Question [Slot 2] with Solution 11

Question

Aron bought some pencils and sharpeners. Spending the same amount of money as Aron, Aditya bought twice as many pencils and 10 less sharpeners. If the cost of one sharpener is ? 2 more than the cost of a pencil, then the minimum possible number of pencils bought by Aron and Aditya together is

  1. 30
  2. 33
  3. 27
  4. 36
Option: 2
Solution:

Let the price of each pencil be Rs. \(x\) and price of each sharpens be Rs. y

Aron \(y - x = 2\quad  \Rightarrow \quad \therefore x = y - 2\)

\(a(y - 2) + b(y) = 2a(y - 2) + (b - 10)y\)

\(10y = a(y - 2) \to (1)\)

Required value \( = 3a\)

From \((1)\quad a = \frac{{10y}}{{y - 2}}a \in {I^ + }\)

Its possible only when \(y = 22\)

\(\therefore a = 11\)

Required answer =33

CAT Online Course @ INR 13999 only

CAT 2020 Quant questions with Solutions

CAT online Courses

FREE CAT Prep Whatsapp Group

CAT 2024 Online Course at affordable price