CAT 2020 Quant Question [Slot 3] with Solution 25

Let the total marks be T and scores of Bishnu, Asha and Ramesh be a, b and c respectively.

Given, \(a = 52\% \) of \(T = c - 23\) and \(b = 64\% \) of \(T = c + 34\)

Hence, \((64 - 52)\% \) of \(T = (c + 34) - (c - 23) = 57\)

i.e. \(12\% \) of \(T = 57\)

Hence, score of Geeta \( = 84\% \) of \(T = 7 \times 57 = 399\)