Question

Dick is thrice as old as Tom and Harry is twice as old as Dick. If Dick's age is 1 year less than the average age of all three, then Harry's age, in years, is

Option: 18
Solution:

Let the age of Tom be t.

Ages of Dick and Harry are 3t and 6t respectively.

Given, \(3t = \frac{{t + 3t + 6t}}{3} - 1 \Rightarrow 9t = 10t - 3 \Rightarrow t = 3\)

Age of Harry \( = 6 \times 3 = 18\)

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