Question
Two persons are walking beside a railway track at respective speeds of 2 and 4 km per hour in the same direction. A train came from behind them and crossed them in 90 and 100 seconds, respectively. The time, in seconds, taken by the train to cross an electric post is nearest to
- 87
- 82
- 75
- 78
Option: 2
Solution:
Solution:
Let the length of the train be l and its speed be s. Given \(\frac{l}{{(s - 2) \times \frac{5}{{18}}}} = 90;\frac{l}{{(s - 4) \times \frac{5}{{18}}}} = 100\)
\( \Rightarrow 90(s - 2) \times \frac{5}{{18}} = 100(s - 4) \times \frac{5}{{18}} \Rightarrow s = 22\)
\(\therefore \) Length of the train =500 m.
Hence the required time to cross a lamp post \( = \frac{{500}}{{22 \times \frac{5}{{18}}}}\)
i.e., 81.81 (or) 82 sec.
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