# CAT 2020 Quant Question [Slot 3] with Solution 22

Question

Two alcohol solutions, A and B, are mixed in the proportion 1:3 by volume. The volume of the mixture is then doubled by adding solution A such that the resulting mixture has 72% alcohol. If solution A has 60% alcohol, then the percentage of alcohol in solution B is

1. $94\%$
2. $92\%$
3. $90\%$
4. $89\%$
Option: 2
Solution:

Let the quantity of solutions A and B mixed initially be p and 3p respectively.

After an additional 4p of solution A is added $60\%$ of $(1p + 4p) + x\%$ of $3p = 72\%$ of $(1p + 4p + 3p)$ $\Rightarrow x = 92$

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