Question
Two alcohol solutions, A and B, are mixed in the proportion 1:3 by volume. The volume of the mixture is then doubled by adding solution A such that the resulting mixture has 72% alcohol. If solution A has 60% alcohol, then the percentage of alcohol in solution B is
- \(94\% \)
- \(92\% \)
- \(90\% \)
- \(89\% \)
Option: 2
Solution:
Solution:
Let the quantity of solutions A and B mixed initially be p and 3p respectively.
After an additional 4p of solution A is added \(60\% \) of \((1p + 4p) + x\% \) of \(3p = 72\% \) of \((1p + 4p + 3p)\) \( \Rightarrow x = 92\)
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