CAT 2020 Quant Question [Slot 2] with Solution 25

Let the principal be P.

Given \(\left( {P \times {{\left( {1 + \frac{5}{{100}}} \right)}^2} - P} \right) - \left( {\frac{{P \times 3 \times 3}}{{100}}} \right) = 1125\)

\( \Rightarrow P(0.1025 - 0.09) = 1125\)

\( \Rightarrow P = 90,000\)