# CAT 2020 Quant Question [Slot 1] with Solution 13

Question

Among 100 students, ${x_1}$ have birthdays in January, ${x_2}$ have birthdays in February, and so on. If ${x_0} = \max \left( {{x_1},{x_2}, \ldots ,{x_{12}}} \right),$ then the smallest possible value of ${x_0}$ is

1. 9
2. 10
3. 8
4. 12
Option: 1
Solution:

Given ${x_0} = \left( {{x_1},{x_2}, \ldots \ldots \ldots {x_{12}}} \right)$

If ${x_1} = {x_2} = {x_3} = {x_4} = 9;{x_5} = {x_6} = \ldots \ldots { \times _{12}} = 8$

$\therefore {x_0} = \max (9,9,9,9,8,8 \ldots .8)$

The minimum value if ${x_0}$ is 9 .

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