Question
Let k be a constant. The equations kx + y = 3 and 4x + ky = 4 have a unique solution if and only if
- |k| ≠ 2
- |k| = 2
- k ≠ 2
- k = 2
Option: 1
Solution:
Solution:
Simultaneous equation have a unique solution only if \(\frac{{{a_1}}}{{{a_2}}} \ne \frac{{{b_1}}}{{{b_2}}}\)
From the given equations, a unique solution would exist only if \(\frac{k}{2} \ne \frac{2}{k}\)
\( \Rightarrow {k^2} \ne 4 \Rightarrow |k| \ne 2\)
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