CAT 2020 Quant Question [Slot 1] with Solution 24

Original quantity of dye and water in the original solution i.e., 16 litres (i.e. \(\left. { = 40 \times \frac{2}{5}} \right)\) and 24 litres (i.e. = \(40 - 16)\)

Quantity of water added \( = 16\) litres (As 1 part \( = 8\) litres). Quantity of dye and water removed \( = \frac{1}{4} \times \frac{2}{7}(56)\) i.e., 4 litres and \(\frac{1}{4} \times \frac{5}{7} \times (56)\) i.e., 10 litres. Final quantity of dye and water is 12 litres and 30 litres.

\(\therefore \) Quantity of dye to be added to make the ratio of dye and water again 2: 3 i.e., 8 litres.