CAT 2020 Quant Question [Slot 1] with Solution 23

Given A, B and C are positive integers such that \(A + \frac{{B + C}}{2} = 5 \cdots (1)\)

\(B + \frac{{A + C}}{2} = 7 \cdots (2)\)

\((2) - (1) \Rightarrow \frac{B}{2} - \frac{A}{2} = 2 \Rightarrow B - A = 4\)

The least value for A=1 in which case B=5.

Hence \(A + B = 6\)