Question:
A parallelogram ABCD has area 48 sqcm. If the length of CD is 8 cm and that of AD is s cm, then which one of the following is necessarily true?
- s≥6
- s≠6
- s≤6
- 5≤s≤7
Correct Answer: 1
We can see that area of parallelogram ABCD = 2×Area of triangle ACD
48 = 2×Area of triangle ACD
Area of triangle ACD = 24
\((1/2)×CD×DA×sinADC = 24\)
\(AD×sinADC = 6\)
We know that \(sin\theta \) \( \le \) 1, Hence, we can say that AD \( \ge \) 6
\( \Rightarrow \) s \( \ge \) 6
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