Bodhee Prep-Online CAT Coaching | Online CAT Preparation | CAT Online Courses

Get 10% OFF on CAT 25 Courses. Code: BODHEE10 Valid till 07th April Enroll Now

CAT 2018 [SLOT 2] Quant Question with Solution 14

Question:
Let t1, t2,… be real numbers such that t1+t2+…+tn = 2n2+9n+13, for every positive integer n ≥ 2. If tk=103, then k equals

Show Answer
Correct Answer: 24
$t_{1}+t_{2}+\ldots+t_{n}=2 n^{2}+9 n+13 \rightarrow(1)$
$t_{1}+t_{2}+\ldots+\ {tn}-1=2(n-1)^{2}+9(n-1)+13 \rightarrow(2)$
From $(2)-(1),$ we get $t_{n}=\left(2 n^{2}+9 n+13\right)-\left(2(n-1)^{2}\right.$
$+9(n-1)+13 )=4 n+7$
Given $t_{k}=103=>4 k+7=103 \Rightarrow k=24 \quad$

CAT Online Course
Also Check: 841+ CAT Quant Questions with Solutions

CAT 2018 Slot-1


CAT 2018 Slot-2


CAT Quant Questions with Video Solutions

30 must do CAT Quant Questions with Video Solutions
CAT online Courses

FREE CAT Prep Whatsapp Group

CAT 2025 best online courses

Online CAT Courses