**Note:**These Quant questions have been selected from

**1000+**CAT Quant Practice Problems with video solutions of Bodhee Prep’s Online CAT Quant Course

**Question 1:**

ABC is an isosceles triangle with sides AB=AC=5. D is a point in between B and C such that BD=2 and DC=4.5. Find the length of AD.

Topic: triangles

[1] \(2\sqrt 2 \)

[2] \(3\)

[3] \(4\)

[4] \(2\sqrt 3 \)

**Answer: **Option: 3

**Question 2:**

Let \(P=\frac{1}{{{10}^{2}}+1}+\frac{2}{{{10}^{2}}+2}+\frac{3}{{{10}^{2}}+3}+...+\frac{10}{{{10}^{2}}+10}\) then which of the following is the best approximate value of P.

Topic: series

[1] \(0.42\)

[2] \(0.52\)

[3] \(0.57\)

[4] \(0.62\)

**Answer: **Option: 2

**Question 3:**

How many rectangles can be formed by taking the four vertices of 18-sided regular polygon.

Topic: permutation and combination

**Answer: **36

**Question 4:**

Find the smallest number which has 6 distinct factors

Topic: factors

**Answer: **12

**Question 5:**

If Rohit drives at 20kmph, he reaches office at 3 pm. If he drives at 30kmph, he reaches office at 11 am. At what speed he should drive if he wishes to reach office at 1 pm.

Topic: speed time and distance

[1] 25 kmph

[2] 24 kmph

[3] 27 kmph

[4] None of these

**Answer: **Option: 2

### CAT Quant Practice Sets [Video Explanations]

CAT Quant Questions Set 02

CAT Quant Questions Set 03

CAT Quant Questions Set 04

CAT Quant Questions Set 05

CAT Quant Questions Set 06

#### CAT Quant Online Course

- 1000+ Practice Problems
- Detailed Theory of Every Topics
- Online Live Sessions for Doubt Clearing
- All Problems with Video Solutions

₹ 3499

do you have exclusive PACKAGE OF video solutions of last 10-15 years CAT EXAMS? I AM INTERESTED IN JUST THAT. I AM HELPING A GIRL APPEARING FOR CAT 2019 EXAM

We have already included all the good questions from CAT and other MBA entrance exams in our course.

All these questions are with Video explanations

Can you tell the name of the theorem that you said in the first quetion

stewarts theorem

Sir, for question no. 23:- we can do as x+y=2-z

=> cubing both sides:- x3+y3+z3=8-(2-z)(6z+3xy)

=>as given that x3+y3+z3=8, then (2-z)(6z+3xy)=0 => z=2(considering an integer value for easy output) ,now putting z value in every eqn given :- x+y=0

x2+y2=2

x3+y3=0

from the above three eqns we find that if one of x or y is +ve then another ll be -ve but both ll be of same magnitude i.e. (+-)1….thus x4+y4+z4=18

Set 1 Question 5.

I want to know the below logic would be wrong.

Distance is constant. If the Speed increases by 10km/hr, the time decreases by 4 hours.

So to decrease time by 2 hours, Speed can be increased by 5km/hr.

20 + 5= 25 kmph.

I understand something might be wrong with this logic but could someone help pinpoint that?