# CAT Quant Questions with Video Solutions

Note: These Quant questions have been selected from 1000+ CAT Quant Practice Problems with video solutions of Bodhee Prep’s Online CAT Quant Course
Question 1:
ABC is an isosceles triangle with sides AB=AC=5. D is a point in between B and C such that BD=2 and DC=4.5. Find the length of AD.
Topic: triangles

[1] $2\sqrt 2$
[2] $3$
[3] $4$
[4] $2\sqrt 3$

Question 2:
Let $P=\frac{1}{{{10}^{2}}+1}+\frac{2}{{{10}^{2}}+2}+\frac{3}{{{10}^{2}}+3}+...+\frac{10}{{{10}^{2}}+10}$ then which of the following is the best approximate value of P.
Topic: series

[1] $0.42$
[2] $0.52$
[3] $0.57$
[4] $0.62$

Question 3:
How many rectangles can be formed by taking the four vertices of 18-sided regular polygon.
Topic: permutation and combination

Question 4:
Find the smallest number which has 6 distinct factors
Topic: factors

Question 5:
If Rohit drives at 20kmph, he reaches office at 3 pm. If he drives at 30kmph, he reaches office at 11 am. At what speed he should drive if he wishes to reach office at 1 pm.
Topic: speed time and distance

[1] 25 kmph
[2] 24 kmph
[3] 27 kmph
[4] None of these

### CAT Quant Practice Sets [Video Explanations]

CAT Quant Questions Set 02
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CAT Quant Questions Set 04
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### 6 thoughts on “CAT Quant Questions with Video Solutions”

1. MAHESH AGGARWAL says:

do you have exclusive PACKAGE OF video solutions of last 10-15 years CAT EXAMS? I AM INTERESTED IN JUST THAT. I AM HELPING A GIRL APPEARING FOR CAT 2019 EXAM

We have already included all the good questions from CAT and other MBA entrance exams in our course.
All these questions are with Video explanations

2. Rajaraman says:

Can you tell the name of the theorem that you said in the first quetion

3. Abinash says:

Sir, for question no. 23:- we can do as x+y=2-z
=> cubing both sides:- x3+y3+z3=8-(2-z)(6z+3xy)
=>as given that x3+y3+z3=8, then (2-z)(6z+3xy)=0 => z=2(considering an integer value for easy output) ,now putting z value in every eqn given :- x+y=0
x2+y2=2
x3+y3=0
from the above three eqns we find that if one of x or y is +ve then another ll be -ve but both ll be of same magnitude i.e. (+-)1….thus x4+y4+z4=18

4. Siddharth says:

Set 1 Question 5.

I want to know the below logic would be wrong.

Distance is constant. If the Speed increases by 10km/hr, the time decreases by 4 hours.
So to decrease time by 2 hours, Speed can be increased by 5km/hr.

20 + 5= 25 kmph.

I understand something might be wrong with this logic but could someone help pinpoint that?