Question:
A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now
- 35.2
- 30.3
- 20.5
- 25.4
Correct Answer: 1
Final quantity of alcohol in the mixture = \(\frac{{700}}{{700 + 175}}×{(\frac{{90}}{{100}})^2}×[700 + 175]\) = 567 ml
Therefore, final quantity of water in the mixture = 875 - 567 = 308 ml
Hence, the percentage of water in the mixture = \(\frac{{308}}{{875}} \times 100\) = 35.2 %
CAT Online Course
Also Check: 841+ CAT Quant Questions with Solutions