# Time Speed and Distance Questions for CAT

CAT 2020 MOCK Test Series at INR 1000/- only.
Question 1: I walk to a town at $3_2^1$ kmph, rest there for 45 minutes and ride back at $7_2^1$ kmph. Find the distance to the town, if the total time spent by me is 6 hrs 37 min.
 14 km
 7km
 5 km
 8 km

Option: 1

Explanation:

Let the distance be D.

Therefore, $\begin{array}{l}\frac{D}{{3.5}} + \frac{{45}}{{60}} + \frac{D}{{7.5}} = 6\frac{{37}}{{60}}\\ \Rightarrow D = 14\;cm\end{array}$

Question 2: A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 seconds and 10 seconds respectively. The length of the train (in metres) is
 45
 54
 50
 72

Option: 3

Explanation:

Let the length of train be x km and its speed be y km/hr.

Then, $\frac{x}{{y - 2}} = \frac{9}{{60 \times 60}}{\rm{ and }}\frac{x}{{y - 4}} = \frac{{10}}{{60 \times 60}}$

=> 9y – 3600x = 18 and 10y -3600x =40

=> y- 400x = 2 and y – 360x =4

Therefore, 40x = 2 or $x$ m

Question 3: A man reaches his office 30 min late, if he walks from his home at 3 km per hour and reaches 40 min early if he walks at 4 km per hour. How far is his office from his house?
 7km
 14 km
 5 km
 3 km

Option: 2

Explanation:

Time gained = 30 + 40 = 70 min =$\frac{{70}}{{60}}$hrs.

Let the distance be x km.

Therefore, $\frac{x}{3} - \frac{x}{4} = 70 \times \frac{1}{{60}} \Rightarrow x = 14$ km

Question 4: Raju, walking at the rate of 6 kmph, covers a certain distance in three hours. In how much time will Raju cover this distance running at the speed of 18 kmph?
 1 hour
 3 hours
 60 hours
 22 hours

Option: 1

Explanation:

Let the distance be X.

=>Distance = Speed x Time taken = 6 x 3 = 18 km.

Now, speed = 18 km/hr.

=>Time taken = Distance/Speed = 18/ 18 = 1 hour.

Question 5: Two cyclists start together to travel to a certain destination, one at the rate of 4 kmph and the other at the rate of 5 kmph. Find the distance if the former arrives half an hour after the latter.
 2 km
 10m
 10000m
 1 km

Option: 3

Explanation:

Let the distance be X km. Now Time= distance/ speed.

=>Time for the first rider = X/14.

Similarly, time for the second cyclist = X/5.

Given that: X/14 – X/5 =1/2

=> X= 10 km = 10000 m