Bodhee Prep-Online CAT Coaching | Online CAT Preparation | CAT Online Courses

Get 10% OFF on CAT 24 Course. Code: BODHEE10. Valid till 30th June Enroll Now
| Best Online CAT PreparationFor Enquiry CALL @ +91-95189-40261

# CAT 2021 Quant Question [Slot 1] with Solution 22

Question
If r is a constant such that $\mid {x^2} - 4x - 13\mid = r$ has exactly three distinct real roots, then the value of r is
1. 17
2. 21
3. 15
4. 18
Option: 1
Solution:

The quadratic equation of the form $\mid {x^2} - 4x - 13\mid = r$ has its minimum value at x = -b/2a, and hence does not vary irrespective of the value of x.
Hence at x = 2 the quadratic equation has its minimum.
Considering the quadratic part : $\left| {{x^2} - 4 \cdot x - 13} \right|$. as per the given condition, this must-have 3 real roots.
The curve ABCDE represents the function $\left| {{x^2} - 4 \cdot x - 13} \right|$. Because of the modulus function, the representation of the quadratic equation becomes :
ABC'DE.
There must exist a value, r such that there must exactly be 3 roots for the function. If r = 0 there will only be 2 roots, similarly for other values there will either be 2 or 4 roots unless at the point C'.
The point C' is a reflection of C about the x-axis. r is the y coordinate of the point C' :
The point C which is the value of the function at x = 2, = ${2^2} - 8 - 13$
= -17, the reflection about the x-axis is 17.
Alternatively,
$\mid {x^2} - 4x - 13\mid = r$ .
This can represented in two parts :
${x^2} - 4x - 13\; = \;r\;if\;r\;is\;positive.$
${x^2} - 4x - 13\; = \; - r\;if\;r\;is\;negative.$
Considering the first case : ${x^2} - 4x - 13\; = r$
The quadratic equation becomes : ${x^2} - 4x - 13 - r\; = \;0$
The discriminant for this function is : ${b^2} - 4ac\; = \;16 - \;\left( {4 \cdot \left( { - 13 - r} \right)} \right) = 68 + 4r$
SInce r is positive the discriminant is always greater than 0 this must have two distinct roots.
For the second case :
${x^2} - 4x - 13 + r\; = \;0$ the function inside the modulus is negaitve
The discriminant is $16\; - \;\left( {4 \cdot \left( {r - 13} \right)} \right)\; = \;68 - 4r$
In order to have a total of 3 roots, the discriminant must be equal to zero for this quadratic equation to have a total of 3 roots.
Hence $\;68 - 4r\; = \;0$
r = 17, for r = 17 we can have exactly 3 roots.
CAT Online Course @ INR 13999 only

## CAT 2021 Quant questions with Solutions

##### CAT online Courses

FREE CAT Prep Whatsapp Group

FREE CAT Quant Topic Tests (Video Solutions)