CAT 2018 LRDI Question Paper with Solution [SLOT 2]

From the given information we can find which product belong to which company. In the given figure the products (number) would belong to the following companies

So also the entire graph can be divided into four equal parts with the bottom left part having products in the No hope category, the bottom right part with products in the Blockbuster category, the top left part with products in the Doubtful category and the top right part with products in the promising category.

Question 1:

The areas of all the products in the different categories are

No-hope – 4 + 4 + 3 + 2 + 1 + 1 = 15

Blockbuster – 2 + 4 + 3 + 6 + 6 +6 + 9 = 36

Doubtful – 2 + 1+ 6 + 6 + 1 + 9 + 4 = 29

Promising – 2 + 9 + 3 = 14

As the areas is proportional to the revenue the corresponding product, products under Blockbuster category had the highest revenue.

Ans : Blockbuster

Question 2:

The number of products of Bravo in the different categories are

No-hope (bottom left) – 1

Doubtful (top left) – 3

Promising (top right) – 1

Blockbuster (bottom right) – 2

The correct sequence is 1, 3, 1, 2

Ans : 1, 3, 1, 2

Question 3:

Revenue of Bravo from No-hope products – 4

Revenue of Charlie from No-hope products – 4.

The statements is true.

Alfa's revenue from Blockbuster products

Charlie revenue from Promising products – 9

The statement is true

Total revenue from No-hope products – 15

Total revenue from Doubtful products – 29

The statement is true

Bravo's revenue from Blockbuster products – 6 + 4 = 10

Alfa's revenue from Doubtful products – 6 + 4 + 1 + 1= 12

The statement is not true

Ans : Bravo's revenue from Blockbuster products was

greater than Alfa's revenue from Doubtful products

Question 4:

The total revenue of Bravo is 4 (No. hope) + 10 (Blockbuster) + 17 (Doubtful) + 3 (Promising) = 34

crore. Ans : 34 .

Question 1:

Let the total market size be 100 units. The sales of Azra, Bysi, Cxqi and dipq would be 40, 25, 15 and 20 units respectively.

The revenue would be as follows

Azra = 40 x 15,000 = 6.0 lac

Bysi = 25 x 20,000 = 5.0 lac

Cxgi = 15 x 30,000 = 4.5 lac

Dipq = 20 x 25,000 = 5.0 lac

The brand with the highest revenue is Azra.

Ans : Azra

Question 2:

The profits for the different brands, assuming revenue as in the previous question would be

Azra $- 6.0$ lac $\times \frac { 10 } { 100 } = 60,000$

Bysi $- 5.0$ lac $\times \frac { 30 } { 100 } = 1,50,000$

Cxgi $- 4.5$ lac $\times \frac { 40 } { 100 } = 1,80,000$

Dipq $- 5.0$ lac $\times \frac { 30 } { 100 } = 1,50,000$

The profit is the highest for Cxqi

Ans : Cxqi

Question 3:

The new market share, selling prices and profitability for the different brands are

Now the total sales is 140 units.(Increase of 40%) The profits are as follows

Azra $- 49 \times 15,000 \times \frac { 10 } { 100 } = 73,500$

Bysi $- 28 \times 20,000 \times \frac { 30 } { 100 } = 1,68,000$

Cxgi $- 42 \times 18,000 \times \frac { 20 } { 100 } = 1,51,200$

Dipq $- 21 \times 25,000 \times \frac { 30 } { 100 } = 1,57,500$

The profit is the highest for Bysi

Ans : Bysi

Question 4:

The profits increased for Azra (60,000 – 73,500) for

Bysi (1,50,000 – 1, 68,000) and Dipq (1,50,000 –

1,57,500)

Ans : Azra, Bysi, Dipq

From the given information,

Balaram is the third person to enter room 101.

Erina was allotted either room 102 or 103.

Three persons entered the room before Fatima. It means Fatima and Akil entered into room 101.

Ganeshan entered room 102 with only one other person. Thus, only Erina entered room 103.

Chitra was the last person to enter the room. Thus, Chitra entered room 102 with Ganeshan.

Divya, who was the second person to enter room 101 From the above information we get the arrangement as follows.

Question 1:

Divya entered room 101.

Ans : Definitely room 101

Question 2:

No one entered into the room 102 before Ganeshan.

Ans : No one

Question 3:

Erina entered room at 07:45am as in room 101- Divya and Balaram entered before Fatima and Ganeshan entered the room before Chitra, thus Divya, Balaram and Ganeshan entered room before Chitra and Fatima in any order.

Ans : 7:45 am

Question 4:

From the information, Ganeshan entered room at 7:10 am, Divya entered room at 7:15 am and Balaram

entered room at 7:25 am.

Ans : 7:25 am

The base exchange rates of currencies A, B and C with  respect to L is in the ratio 100 : 120 : 1.

The given information can be tabulated as follows

The outlet received 88,000 units of L by selling A and the ratio of amounts of L used to by A and B are in the ratio 5 : 3 and from the sales of A and B are in the ratio 5 : 9.

This set is best solved by looking at the choices for the question which asked for the base exchange rate of currency C. From that we have only two possible value for the base exchange rates for A, B and C 100,120 and 1 or 200, 240 and 2.

Assuming L to be100 for A.

Units sold of $\mathrm { A } = \frac { 88,000 } { 110 } = 800$

As the net addition is 800, the units of A bought is 1600 Amount of L used in buying 1600 units is 1600 x 0.95

x 100 = 152000 As the amount used to buy A and B are in the ratio 5 : 3, the amount used to buy B is $\frac { 152000 } { 5 } \times 3 = 91,200$

Number of units of B bought = $\frac { 91,200 } { 114 } = 800$

As the net addition of B is zero, number of units of B sold = 800.

The amount received = 800 x 132 = 105600

The amount received form selling A = 88,000

As 88,000 : 105600 is not in the ratio 5 : 9 as given in the data the base exchange rate for A is not 100 and has to be 200.

Units sold for $\mathrm { A } = \frac { 88000 } { 220 } = 400$

As net addition is 800, the units of A bought is 1200.

Amount of L used in buying 1200 units of A = 1200 x 0.95 x 2000 = 228000.

As the amount used to buy A and B are in the ratio 5 :3, quantity of L used to buy B is $\frac { 228000 } { 5 } \times 3 = 136800$

Number of units of $\mathrm { B }$ bought $= \frac { 136800 } { 228 } = 600$

As the net addition in B is zero, the number of units of B sold = 600.

The amount received from selling B = 600 x 264= 158400

The amount received from selling A = 88,000

The required ratio $\frac { 88,000 } { 158400 } = \frac { 5 } { 9 }$

Question 1:

Number of units of currency A bought 400 + 800 = 1200

Question 2:

As the net addition in the number of units of C is 3,000 and the buying and selling rates are in the ratio 0.95 and 1.1, assuming x units are sold 0.95 (x + 3000) = 1.1 (x)

0.15x = 2850

X= 19000

Question 3:

The base exchange rate of currency B with respect to L is 240.

Question 4:

The buying exchange rate of currency C with respect to L on that day was 1.90.

The given data can be represented as follows.

f + g + d =10 (given)

g + e = b (given)

Since f + g + d = 10, g = 7 = 2g – 1

Therefore, 2g = 8  f = 4

Thus, g = 4, c = 8, a = 7 and f + d = 6

b + e = 39 – (G + c) = 14

therefore g + 2e = 14 Hence, e = 5 and b = 9

Since, L is maximum we get the following cases.

Case (i)

G = 17 K = 20 L = 21 d = 2 f = 4

Case (ii)

G = 17 K = 19 L = 22 d = 1 f = 5

Case (iii)

G = 17 K = 18 L = 23 d = 0 f = 6

Question 1:

G and L but not K = f = 4. Ans : 4

Question 2:

The given condition is possible in case (ii). Hence, the number of students enrolled in L = 22. Ans : 22

question 3:

From g = 4, one person moves to f, one person to d and two persons to e. Then the value of G and K = d + g = 2. Ans : 2

Question 4:

From the above G and L = f = 6. Ans : 6

Let a, b, c and d be the weights of parameters F, R, P and I respectively.

Given,

(i) 30a + 20b + 20c + 40d > 40a + 30b + 20c + 20d

(ii) 40a + 30b + 20c + 20d > 40a + 20b + 20c + 30d

(iii) 50a + 50b + 40c + 50d > 50a + 50b + 50c + 40d

From (i), 2d > a + b

From (ii), b > d

From (iii), d > c

$\Rightarrow$ b > d > c

a, b, c and d are 0.1, 0.2, 0.3 and 0.4 in any order.

d cannot be 0.1 or 0.2. (∵ 2d cannot be greater than a + b)

d can be 0.3 or 0.4, but given b > d.

$\Rightarrow$  b = 0.4, d = 0.3

2(0.3) > 0.4 + a

a < 0.2

a = 0.1, c = 0.2

Question 1

Weight of faculty parameter is 0.1.

Ans : 0.1

Question 2

Three colleges received AAA rating.

Ans : 3

Question 3

Height overall score among the eight colleges is 48.

Ans : 48

Question 4

No college has score between 31 and 40 (both inclusive).

 Ans : 0

Given 'peacock is designated as the national bird of India' is coded as ' 5688999 35 1135556678 56 458 13666689 1334 79 13366'

9 is the code for o and c from the words peacock and of.

F is coded as 7 from the word of.

I is coded as either 3 or 6 from the word India, but from the word 'is' and 'designated' code for 'I' is 3.

S is coded as 5 from the word is.

A is coded as 6 from the word 'as'.

N is coded as 6 from the word national.

Thus D is coded as 1 from the word India.

E is coded as 5 from the word designated.

T is coded as 8 from the word 'the' and 'National'.

Thus H is coded as 4 from the word 'the'. G is coded as 7. L is coded as 1 from the word 'National'.

P and K are coded as 8 from the word 'peacock'. B and R are coded as 3 and 4 many order from the word 'bird'.

We get the codes as follows

.

B and R is coded as 3 or 4.

Question 1

L is coded as '1'. Ans : 1

Question 2

Either 3 or 4 is the code for B. Ans : 3 or 4

Question 3

The code for 8 and 9 is identified. Ans : 2

Question 4

S, U, V cannot be coded with same digit.

Ans : S, U, V

Number of young visitors = 2 x number of middle age visitors

Number of middle age visitors = 2 x number of old visitors

Total number of tickets sold = total number of visitors = 140

Hence, the number of young visitors = 80, the number of middle age visitors = 40 and the number of old visitors = 20

The given data can be tabulated as follows.

Question 1

Since half of the platinum tickets were purchased by young visitors, the remaining half were purchased by old and middle age visitors. Since these two are equal, half of total number of platinum tickets should be an even number. Among the given values, this is possible only for 32 and 36.

In case of 36, Old- Platinum = 9. In that case 2a = 11. But this is not possible. Hence, the total number of platinum tickets sold can only be 32.

Ans : 32

Question 2

Let Old – platinum = Middle aged – Economy = x

We get x + 2a = 20 and a + x + 38 = 55

By solving these two equations we get x = 3.

Ans : 3

Question 3

If the number of Old visitors buying Gold tickets was strictly greater than the number of Young visitors buying Gold tickets, then the number of Middle-aged visitors buying Gold tickets was

The maximum possible value of Young - gold = x – 1

Then young – platinum = 80 – (38 + x – 1) = 43 – x

Hence, Old – platinum + Middle age – Platinum = 43 – x

Total old + Middle age = 60

(Old – platinum + Middle age – platinum) + (Old – gold + Middle age – gold ) + (Old – economy + Middle age – economy) = 60

Hence, Old – gold + Middle age – gold = x

Thus, Middle age – gold = 0

Ans : Zero

Question 4

Since Old – Economy + Middle age – economy = 17, these two can never be equal. Hence, the statement that “The numbers of Old and Middle-aged visitors buying Economy tickets were equal” is false.

Ans : “The numbers of Old and Middle-aged visitors buying Economy tickets were equal”