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CAT 2017 [slot 2] Question with solution 27

Question 61:
Let $a_{1},a_{2},a_{3},a_{4},a_{5}$ be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with $2a_{3}$

If the sum of the numbers in the new sequence is 450, then $a_{5}$ is


Answer: 51
Explanation:

Sum of the sequence of even numbers is $2a_{3} + (2a_{3} - 2) + (2a_{3} - 4)$ $+ (2a_{3} - 6) + (2a_{3} - 8) = 450$
=> $10a_{3} - 20 = 450$
=> $a_{3} = 47$
Hence $a_{5} = 47 + 4 = 51$


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