Question 55: If the product of three consecutive positive integers is 15600 then the sum of the squares of these integers is
1777
1785
1875
1877
Option: 4 Explanation:
$(x -1)x(x+1) = 15600$ => $x^3 - x= 15600 $ The nearest cube to 15600 is 15625 = $25^3$ We can verify that x = 25 satisfies the equation above. Hence the three numbers are 24, 25, 26. Sum of their squares = 1877