Question 46: A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm and moves towards point A at a uniform speed which is double that of the motorbike. They meet at 3:40 pm at a point which is 168 km away from A. What is the distance, in km, between A and B?
364
378
380
388
Option: 2 Explanation:
Let the distance traveled by the car be x KMs Distance traveled by the bike = 168 KMs Speed of car is double the speed of bike => $\frac{x}{3:40 - 2:00}$ = $2 \times \frac{168}{3:40 - 1:00}$ => $\frac{x}{100}$ = $2 \times \frac{168}{160}$ => x = 210 Hence the distance between A and B is x + 168 = 378 KMs