Question 17: Let ABC be a right-angled isosceles triangle with hypotenuse BC. Let BQC be a semi-circle, away from A, with diameter BC. Let BPC be an arc of a circle centered at A and lying between BC and BQC. If AB has length 6 cm then the area, in sq cm, of the region enclosed by BPC and BQC is
$9\pi-18$
18
$9\pi$
Option: Explanation:
The image of the figure is as shown.
AB = AC = 6cm. Thus, BC = $\sqrt{6^2 + 6^2}$ = 6?2 cm
The required area = Area of semi-circle BQC - Area of quadrant BPC + Area of triangle ABC