# Time Speed and Distance Questions for CAT

Question 16: Raghunandan completes 9/30th of his total journey by ship, 5/18th by a horse carriage and the remaining 10 km on foot. The length of the total journey is
 450/19 km
 24.62 km
 27.2 km
 92 km

Option: 1

Explanation:

Let the total length of journey, performed by Raghunandan be x km.

According to the given condition, $x - \frac{9}{{30}}x - \frac{5}{{18}}x = 10$

$\Rightarrow \frac{{90x - 27x - 25x}}{{90}} = 10 \Rightarrow 38x = 10 \times 90$

Or $x = \frac{{10 \times 90}}{{38}} = \frac{{450}}{{19}}km$

Question 17: Walking at 4/7th of his usual speed, Ramu gets late by 15 minutes. Find the time he would have taken walking at his usual speed.
 25 min
 20 min
 30 min
 24 min

Option: 2

Explanation:

Speed = 4/7th of the usual speed.

=>Time required = 7/4th of the usual time.

=> (7/4th of the usual time)- (usual time required) = 15/60 hours.

=> usual time = 1/3 hours = 20 min.

Question 18: If I take as much time in running 15 m as a car takes in covering 36 m, then find the distance I can cover in the time taken by the car to travel 1 km.
 416.6 m
 41.6 m
 4.16 km
 41.6 km

Option: 1

Explanation:

36m = 15 m.

$1000m \equiv \frac{{15}}{{36}} \times 1000 = 416.6m$

Question 19: Ramesh runs 22.4 kmph. How many metres does he run in five minutes?
 1866m
 18.66 km
 2.866 km
 1.432 km

Option: 1

Explanation:

Speed = 22.4 km/hr = 22.4 x 5/18 m/s = 6.22 m/s.

=>In 5 min (300 sec), distance covered = 6.22 x 300 = 1866 m.

Question 20: A handcart has to cover a distance of 120 km in 15 hours. If it covers half the distance in 4/7th of the time, then what speed should it maintain in order to cover the remaining journey in the scheduled time?
 9.33 kmph
 4.6 kmph
 3.1 kmph
 None of these

Option: 1

Explanation:

Time left = 1 - 4/7 = 3/7th of the total scheduled time.

3/7 x 15 = 45/7 hrs; Distance left = 60 km.

Required speed = 60/(45/7) = 9.33 km/hr.

## Time Speed and Distance

Time Speed and Distance Questions for CAT
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