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Question 16: Raghunandan completes 9/30th of his total journey by ship, 5/18th by a horse carriage and the remaining 10 km on foot. The length of the total journey is [1] 450/19 km [2] 24.62 km [3] 27.2 km [4] 92 km

Answer:

Option: 1

Explanation:

Let the total length of journey, performed by Raghunandan be x km.

According to the given condition, \(x - \frac{9}{{30}}x - \frac{5}{{18}}x = 10\)

Or \(x = \frac{{10 \times 90}}{{38}} = \frac{{450}}{{19}}km\)

Question 17: Walking at 4/7^{th} of his usual speed, Ramu gets late by 15 minutes. Find the time he would have taken walking at his usual speed. [1] 25 min [2] 20 min [3] 30 min [4] 24 min

Answer:

Option: 2

Explanation:

Speed = 4/7th of the usual speed.

=>Time required = 7/4th of the usual time.

=> (7/4^{th} of the usual time)- (usual time required) = 15/60 hours.

=> usual time = 1/3 hours = 20 min.

Question 18: If I take as much time in running 15 m as a car takes in covering 36 m, then find the distance I can cover in the time taken by the car to travel 1 km. [1] 416.6 m [2] 41.6 m [3] 4.16 km [4] 41.6 km

Question 19: Ramesh runs 22.4 kmph. How many metres does he run in five minutes? [1] 1866m [2] 18.66 km [3] 2.866 km [4] 1.432 km

Answer:

Option: 1

Explanation:

Speed = 22.4 km/hr = 22.4 x 5/18 m/s = 6.22 m/s.

=>In 5 min (300 sec), distance covered = 6.22 x 300 = 1866 m.

Question 20: A handcart has to cover a distance of 120 km in 15 hours. If it covers half the distance in 4/7th of the time, then what speed should it maintain in order to cover the remaining journey in the scheduled time? [1] 9.33 kmph [2] 4.6 kmph [3] 3.1 kmph [4] None of these

Answer:

Option: 1

Explanation:

Time left = 1 - 4/7 = 3/7th of the total scheduled time.