CAT Quant Questions with Video Solutions

Note: These Quant questions have been selected from 1000+ CAT Quant Practice Problems with video solutions of Bodhee Prep’s Online CAT Quant Course
Question 26:
For any three positive real numbers x, y and z,\(9\left( {25{x^2} + {y^2}} \right) + 25\left( {{z^2} - 3zx} \right) = 15y\left( {3x + z} \right)\) Then :
Topic: progressions

[1] x, y and z are in G.P.
[2] y, z and x are in G.P.
[3] y, z and x are in A.P.
[4] x, y and z are in A.P.

Question 27:
Circles with center A and B are externally tangent to each other and to line m. If the radii of circle A and B are 3 and 1 respectively, Find the area of the shaded region.

Topic: area

[1] \(4\sqrt{3}-\frac{7\pi }{3}\)
[2] \(3\sqrt{3}-\frac{11\pi }{7}\)
[3] \(2\sqrt{3}-\frac{\pi }{3}\)
[4] \(4\sqrt{3}-\frac{11\pi }{6}\)

Question 28:
13 married couples attended a wedding ceremony, each woman gave a pack of chocolates to everyone except her spouse, and no exchange of gifts took place between men. How many gifts were exchanged among these people?
Topic: permutation and combination

[1] 78
[2] 312
[3] 468
[4] 624

Question 29:
Let \(f\left( x \right)=a{{x}^{2}}+bx+c\) and \(f\left( {x + y} \right) = f\left( x \right) + f\left( y \right) + xy\). Given a+b+c=3 , find the value of \(f\left( 10 \right)\)
Topic: functions

Question 30:
Let \(x={{\log }_{4}}9+{{\log }_{9}}28\) then which of the following is true:
Topic: logarithm

[1] 2<x<3
[2] 3<x<4
[3] 4<x<5
[4] None of these

CAT Quant Practice Sets [Video Explanations]

CAT Quant Questions Set 01
CAT Quant Questions Set 02
CAT Quant Questions Set 03
CAT Quant Questions Set 04
CAT Quant Questions Set 05

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6 thoughts on “CAT Quant Questions with Video Solutions

  1. do you have exclusive PACKAGE OF video solutions of last 10-15 years CAT EXAMS? I AM INTERESTED IN JUST THAT. I AM HELPING A GIRL APPEARING FOR CAT 2019 EXAM

    • We have already included all the good questions from CAT and other MBA entrance exams in our course.
      All these questions are with Video explanations

  2. Sir, for question no. 23:- we can do as x+y=2-z
    => cubing both sides:- x3+y3+z3=8-(2-z)(6z+3xy)
    =>as given that x3+y3+z3=8, then (2-z)(6z+3xy)=0 => z=2(considering an integer value for easy output) ,now putting z value in every eqn given :- x+y=0
    from the above three eqns we find that if one of x or y is +ve then another ll be -ve but both ll be of same magnitude i.e. (+-)1….thus x4+y4+z4=18

  3. Set 1 Question 5.

    I want to know the below logic would be wrong.

    Distance is constant. If the Speed increases by 10km/hr, the time decreases by 4 hours.
    So to decrease time by 2 hours, Speed can be increased by 5km/hr.

    20 + 5= 25 kmph.

    I understand something might be wrong with this logic but could someone help pinpoint that?

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