# CAT Quant Questions with Video Solutions

CAT 2020 MOCK Test Series at INR 1000/- only.

Note: These Quant questions have been selected from 1000+ CAT Quant Practice Problems with video solutions of Bodhee Prep’s Online CAT Quant Course
Question 16:
Let $N = 1! \times 2! \times 3! \times ..... \times 99! \times 100!$, and if $\frac{N}{{p!}}$ is a perfect square for some positive integer $p \le 100$, then find the value of p.
Topic: factorials

Question 17:
If ${x^2} + {y^2} = 1$ , find the maximum value of ${x^2} + 4xy - {y^2}$
Topic: maxima minima

 $1$
 $\sqrt 2$
 $\sqrt 5$
 $4$

Question 18:
The compound interest on a certain amount for two years is Rs. 291.2 and the simple interest on the same amount is Rs. 280. If the rate of interest is same in both the cases, find the Principal amount
Topic: sici

 1200
 1400
 1700
 1750

Question 19:
In the diagram given below, the circle and the square have the same center O and equal areas. The circle has radius 1 and intersects one side of the square at P and Q. What is the length of PQ? Topic: circles

 1
 3/2
 $\sqrt {4 - \pi }$
 $\sqrt {\pi - 1}$

Question 20:
What is the remainder when ${{x}^{276}}+12$ is divided by ${{x}^{2}}+x+1$ given that the remainder is a positive integer?
Topic: remainders

### CAT Quant Practice Sets [Video Explanations]

CAT Quant Questions Set 01
CAT Quant Questions Set 02
CAT Quant Questions Set 03
CAT Quant Questions Set 05
CAT Quant Questions Set 06

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### 8 thoughts on “CAT Quant Questions with Video Solutions”

1. MAHESH AGGARWAL says:

do you have exclusive PACKAGE OF video solutions of last 10-15 years CAT EXAMS? I AM INTERESTED IN JUST THAT. I AM HELPING A GIRL APPEARING FOR CAT 2019 EXAM

• admin says:

We have already included all the good questions from CAT and other MBA entrance exams in our course.
All these questions are with Video explanations

• Pavani says:

If f is 3
F(3)
6+3+2 is 11

2. Rajaraman says:

Can you tell the name of the theorem that you said in the first quetion

• anushka says:

stewarts theorem

3. Abinash says:

Sir, for question no. 23:- we can do as x+y=2-z
=> cubing both sides:- x3+y3+z3=8-(2-z)(6z+3xy)
=>as given that x3+y3+z3=8, then (2-z)(6z+3xy)=0 => z=2(considering an integer value for easy output) ,now putting z value in every eqn given :- x+y=0
x2+y2=2
x3+y3=0
from the above three eqns we find that if one of x or y is +ve then another ll be -ve but both ll be of same magnitude i.e. (+-)1….thus x4+y4+z4=18

4. Siddharth says:

Set 1 Question 5.

I want to know the below logic would be wrong.

Distance is constant. If the Speed increases by 10km/hr, the time decreases by 4 hours.
So to decrease time by 2 hours, Speed can be increased by 5km/hr.

20 + 5= 25 kmph.

I understand something might be wrong with this logic but could someone help pinpoint that?

• shaswat says:

the assumption of “to decrease time by 2 hours, speed can be increase by 5km/hr” is wrong. it would be right if you know the initial time and consider from the start but since the journey is already going on, u can’t do that.