CAT Quant Practice Problems

Question: Let f(x) = max (2x + 1, 3 - 4x), where x is any real number. Then the minimum possible value of f(x) is:

\(\frac{1}{3}\)
\(\frac{1}{2}\)
\(\frac{2}{3}\)
\(\frac{4}{3}\)
\(\frac{5}{3}\)
Show Answer
Please Login to see the answer



Back to Main Page

CAT Quant Online Course


  • 1000+ Practice Problems
  • Detailed Theory of Every Topics
  • Online Live Sessions for Doubt Clearing
  • All Problems with Video Solutions
₹ 2999
CAT Quant Practice Problems
4.7 (94.55%) 11 votes