CAT Quant Practice Problems

Question: Let f(x) = max (2x + 1, 3 - 4x), where x is any real number. Then the minimum possible value of f(x) is:
  1. \(\frac{1}{3}\)
  2. \(\frac{1}{2}\)
  3. \(\frac{2}{3}\)
  4. \(\frac{4}{3}\)
  5. \(\frac{5}{3}\)

Correct Option:5

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CAT Quant Practice Problems
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