# CAT Quant Practice Problems

Question: Let f(x) = max (2x + 1, 3 - 4x), where x is any real number. Then the minimum possible value of f(x) is:
1. $\frac{1}{3}$
2. $\frac{1}{2}$
3. $\frac{2}{3}$
4. $\frac{4}{3}$
5. $\frac{5}{3}$

Correct Option:5

## CAT Quant Questions with Video Solutions

CAT Quant Practice Problems
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