CAT Quant Practice Problems

Question: In the following figure, the diameter of the circle is 3 cm. AB and MN are two diameters such that MN is perpendicular to AB. In addition, CG is perpendicular to AB such that AE:EB = 1:2, and DF is perpendicular to MN such that NL:LM = 1:2. The length of DH in cm is

\(2\sqrt 2 - 1\)
\(\frac{{\left( {2\sqrt 2 - 1} \right)}}{2}\)
\(\frac{{\left( {3\sqrt 2 - 1} \right)}}{2}\)
\(\frac{{\left( {2\sqrt 2 - 1} \right)}}{3}\)
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