CAT Quant Practice Problems

Question: In the above diagram, \(\angle ABC = 90^\circ = \angle DCH = \angle DOE = \angle EHK = \angle FKL = \angle GLM = \angle LMN\)

AB = BC = 2CH = 2CD = EH = FK = 2HK = 4KL = 2LM = MN

The magnitude of ∠FGO =


  1. 30°
  2. 45°
  3. 60°
  4. None of these

Correct Option:4

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CAT Quant Practice Problems
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