CAT Quant Practice Problems

Question: In the above diagram, \(\angle ABC = 90^\circ = \angle DCH = \angle DOE = \angle EHK = \angle FKL = \angle GLM = \angle LMN\)

AB = BC = 2CH = 2CD = EH = FK = 2HK = 4KL = 2LM = MN

The magnitude of ∠FGO =

30°
45°
60°
None of these
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CAT Quant Practice Problems
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