[A] 1 : 2
[B] 2 : 1
[C] 1 : 1
[D] 2 : 3
[A] 1 : 2
[B] 1 : 3
[C] 2 : 1
[D] 2 : 3
[A] 17%
[B]

[C]

[D] 15%
Solution :
Initially, the mixture contains 3 litres of alcohol and 12 litres of water. Afterwards, the mixture contains 3 litres of alcohol and 15 litres of water.
percentage of alcohol.
[A] 4 kg
[B] 5 kg
[C] 8 kg
[D] 30 kg
Solution :
Water
In the second mixture:
75 kg spirit is contained in a mixture of 100 kg
18 kg spirit is contained in a mixture of.
So, water to be added=24-20=4 kg
Online CAT Quant Course[A] 25 days
[B] 280/11 days
[C] 180/7 days
[D] 270/11 days
Solution :
Sachin's salary for one day = 1/45th of the sum of money.
For kale's salary for one day = 1/60 of the sum of money.
=> (Sachin + kale)'s salary for one day= 1/45+1/60=7/180th of the sum.
Hence, when they both work together, the sun will last for 180/7 days.
Online CAT Quant Course[A] 2 : 1
[B] 3 : 2
[C] 3 : 4
[D] 1 : 2
Solution :
S.P. Of 1 kg mixture = Rs. 1.75, gain= 25%.
Mean price= Rs.
(Dearer price) : (cheaper price)=20:40=1:2.
Online CAT Quant Course[A] 37 : 35
[B] 19 : 18
[C] 31 : 25
[D] 29 : 35
Solution :
In alloy A, the ratio of iron to Silver=4:5, 5+4=9
In alloy B, the ratio of iron to Silver=7:5, 7+5=12, as the amount to be mixed.
So take the LCM of 9 and 12. hence, we mix 36 gm of A and 36 gm of B.
(the reason for choosing LCM as the amount is to simplify calculations.)
For a: amount of iron= And amount of silver=
For B: amount of iron=And amount of silver=
Hence, Total amount of iron=16+21=37
Total amount of silver=20+15=35
Hence, Final ratio of iron to Silver in the mix of two alloys= 37:35
Shortcut: Required ratio is
[A] 22 kg
[B] 24.7 5kg
[C] 16.50 kg
[D] 20 kg
Solution :
In the first mixture
Milk=
Water=11kg
In the second mixture
If milk is 55kg, then water
Water to be added= 55-33=22kg
Online CAT Quant Course[A] 30%
[B] 35%
[C] 25%
[D] 20%
Solution :
Here percentage alcohol in the mixture is to be found out. So, the quantity of alcoholis kept as numerator
(since 40 ml water is added
Quantity of mixture=100+40).
% alcohol
the mixture contains 20% alcohol.
Online CAT Quant Course[A] 600 ml
[B] 710 ml
[C] 520 ml
[D] None of these
[A] 20 litres
[B] 24 litres
[C] 18 litres
[D] 16 litres
Solution :
let X litre of water be added, initial quantity of water 3/8 x 24 = 9.
X=16 litres.
Online CAT Quant Course[A] 7.5 %
[B] 8%
[C] 2.5 %
[D] 5%
Solution :
let the quantities of two varieties of tea be "5X" kg and "4X" kg respectively.
Thus, cost price..… (1)
and sales price ….. (2)
Profit=(2)-(1)=Rs. 32x
profit %
[A] 1: 1
[B] 9: 25
[C] 25: 9
[D] None of these
Solution :
Let the volume of both the container b x units each. Thus, the first container would containunits of milk and
units of water, whereas the second container would contain
units of milk and
units of water. When the content of both are empty into a third one it would have,
Milk …(1)
And water ….(2)
Thus, the required ratio.
[A] 10 gram
[B] 12 gram
[C] 32 gram
[D] 28 gram
Solution :
from the first ornament, gold
From the second ornament gold
Thus, total gold=32 gm.
Online CAT Quant Course[A] 25: 33
[B] 33: 25
[C] 15: 17
[D] 17: 15
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