A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motor cycle leaves A and moves towards B. Forty-five such motor cycles reach B by 11 am. All motor cycles have the same speed. If the cyclist had doubled his speed, how many motor cycles would have reached B by the time the cyclist reached B?
Correct Answer: Option: 3
Time taken by cyclist to cover the distance AB = 60 min
Given, starting from 10:01 am, every minute a motor cycle leaves A and moves towards B. Forty-five such motor cycles reach B by 11 am.
Also, the speed of all the motor cycles is same.
That means that the 45th moto cyclevwhich started at 10:45 am, reached B exactly at 11 am. Rest all reached B some time before B.
Therefore, each motor cycle takes 15 min to cover the distance AB.
Now, if the cyclist doubles his speed, then he will reach B in 30 min i.e. at 10:30 am.
So, the 15th motor cycle (started at 10:15 am from A) would be the last motor cycle to reach point B at 10:30 am.
Hence, there will be 15 motor cycles would have reached B by the time the cyclist reached B.
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