CAT 2018 Quant Questions

Question:
If x is a positive quantity such that ${2^x} = {3^{{{\log }_5}2}}$ , then x is equal to

 $1 + {\log _3}\frac{5}{3}$ ${\log _5}8$ $1 + {\log _5}\frac{3}{5}$ ${\log _5}9$

Givne that: $2^{x}=3^{\log_{5}{2}}$

$\Rightarrow$ $2^{x}=2^{\log_{5}{3}}$

$\Rightarrow$ $x=\log_{5}{3}$

$\Rightarrow$ $x=\log_{5}{\frac{3*5}{5}}$

$\Rightarrow$ $x=\log_{5}{5}+\log_{5}{\frac{3}{5}}$

$\Rightarrow$ $x=1+\log_{5}{\frac{3}{5}}$.

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