CAT 2018 Quant Questions

Given that x2018y2017 = 1/2 and x2016y2019 = 8, the value of x2 + y3 is

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Correct Answer: 4

$x^{2018} y^{2017}=\frac{1}{2}$…..(1)

and $x^{2016} y^{2019}=8$…..(2)

Dividing (1) by (2), $\frac{x^{2}}{y^{2}}=\frac{1}{16}$

$\frac{x}{y}=\frac{1}{4}$ i.e. $x=\pm \frac{1}{4} y$

$\left(\pm \frac{1}{4} y\right)^{2018} y^{2017}=\frac{1}{2}$



Therefore, $x=\pm \frac{1}{4}y=\pm \frac{1}{2}$

Hence, $x^{2}+y^{3}=\frac{1}{4}+8=\frac{33}{4}$

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