**Question: **

There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratio

229 : 141 | |

220 : 149 | |

239 : 161 | |

251 : 163 |

**Show Answer**

**FREE Trial**of CAT online Full course FREE Registration

Correct Answer: 3

It is given that in drum 1, A and B are in the ratio 18 : 7.

Let us assume that in drum 2, A and B are in the ratio x : 1.

It is given that drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7.

By equating concentration of A

\( \Rightarrow \) \(\frac{{3*\frac{{18}}{{18 + 7}} + 4*\frac{x}{{x + 1}}}}{{3 + 4}} = \frac{{13}}{{13 + 7}}\)

\( \Rightarrow \) \(\frac{{54}}{{25}} + \frac{{4x}}{{x + 1}} = \frac{{91}}{{20}}\)

\( \Rightarrow \) \(\frac{{4x}}{{x + 1}} = \frac{{239}}{{100}}\)

\( \Rightarrow \) \(x = \frac{{239}}{{161}}\)

Therefore, we can say that in drum 2, A and B are in the ratio \(\frac{{239}}{{161}}\) : 1 or 239 : 161.

**Also Check:**841+ CAT Quant Questions with Solutions

## CAT Quant Questions with Video Solutions

CAT Quant Questions Set 01CAT Quant Questions Set 02

CAT Quant Questions Set 03

CAT Quant Questions Set 04

CAT Quant Questions Set 05

CAT Quant Questions Set 06

#### CAT Quant Online Course

- 1000+ Practice Problems
- Detailed Theory of Every Topics
- Online Live Sessions for Doubt Clearing
- All Problems with Video Solutions

**CAT 2018 Questions Paper with Solution PDF **Download