CAT 2018 Quant Questions

A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now

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Correct Answer: 1

Final quantity of alcohol in the mixture = \(\frac{{700}}{{700 + 175}}×{(\frac{{90}}{{100}})^2}×[700 + 175]\) = 567 ml

Therefore, final quantity of water in the mixture = 875 - 567 = 308 ml

Hence, the percentage of water in the mixture = \(\frac{{308}}{{875}} \times 100\) = 35.2 %

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