CAT 2018 Quant Questions

Question:
A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now

35.2
30.3
20.5
25.4
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Correct Answer: 1

Final quantity of alcohol in the mixture = \(\frac{{700}}{{700 + 175}}*{(\frac{{90}}{{100}})^2}*[700 + 175]\) = 567 ml

Therefore, final quantity of water in the mixture = 875 - 567 = 308 ml

Hence, we can say that the percentage of water in the mixture = \(\frac{{308}}{{875}} \times 100\) = 35.2 %

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CAT 2018 Quant Questions
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