Algebra Practice Questions for CAT with Solutions Question 1:
The number of ordered pairs of natural numbers (a, b) satisfying the equation 2a + 3b = 100 is:
 13
 14
 15
 16
Valid solutions:

a = 2; b = 32

a = 5; b = 30

.

.

a = 47; b = 2

No. of solutions = 16. Option D

Question 2:
For how many positive integral values of N, less than 40 does the equation 3a – Nb = 5, have no integer solution
 13
 14
 15
 12
If N is a multiple of 3, then the LHS would be divisible by 3 and RHS won’t be. Number of positive integral values less than 40 which are multiple of 3 = 13. Option A

Question 3:
What are the number of integral solutions of the equation 7x + 3y = 123 for x,y > 0
 3
 5
 12
 Infinite
Valid Solution:

x = 3; y = 34

x = 6; y = 27

.

.

x = 15; y = 6

Number of integral solutions such that x, y > 0 are 5. Option B

Question 4:
The cost of 3 hamburgers, 5 milk shakes, and 1 order of fries at a certain fast food restaurant is $23.50. At the same restaurant, the cost of 5 hamburgers, 9 milk shakes, and 1 order of fries is$39.50. What is the cost of 2 hamburgers, 2 milk shakes, and 2 orders of fries at this restaurant?
 10
 15
 7.5
 Cannot be determined
3H + 5M + 1F = 23.50

5H + 9M + 1F = 39.50

2H + 2M + 2F = ?

Calculate 2(Equation 1) – (Equation 2)

H + M + F = 2×23.5 – 39.5
H + M + F = 7.5
2H + 2M + 2F = 15. Option B

Question 5:
How many integer solutions are there for the equation: |x| + |y| =7?
 24
 26
 14
 None of these
x can take any integer value from [-7,7].

So, there are 15 valid values of x.

For each of these values, there are 2 corresponding values of y. eg: For x = 3; y can be 4 or -4.

Except when x = 7 or -7; where the only possible value of y is 0.

Total valid values of x = 13×2 + 1 + 1 = 28. Option D

Algebra Practice Questions for CAT with Solutions
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